When calcium carbide reacts with $N_{2}$ at $1000^{o} C$ , the compound formed is:

C a C N_{2}

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C a (C N)_{2}

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C a_{3} N_{2}

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C a (N O_{3})_{2}

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Solution

The correct option is A $C a C N_{2}$
$C a C_{2} + N_{2} 1000^{o} C - --- \to C a C N_{2} (n i t r o l i m e) + C$

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