when can a process be spontaneous? the equilibrium constant for a reaction is 10 what will be the sign for delta G? will this reaction be spontaneous?

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Solution

Dear Student,

A process or reaction is spontaneous when the Gibbs Free Energy, $∆ G$ , of the system is negative.

The relationship between Gibbs Free Energy and the equilibrium constant is:

$∆ G^{O} = - R T \ln (K_{e q})$
Since R and T are positive, and ln 10 is 2.302 , $∆ G$ will be negative when K_eq is 10.
So, the reaction will be spontaneous.

Regards

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For a spontaneous reaction the $Δ G$ , equilibrium constant $K$ and $E {^{0}}_{c e l l}$ will be respectively:

For a spontaneous reaction the $Δ G$ , equilibrium constant $(K_{e q})$ and $E_{c e l l}^{0}$ will be respectively

Δ G

K

E_{c e l l}

Δ G^{0}

E_{c e l l}^{0}

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