When cinnabar is heated in air, it finally converted into __________.

H g O

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H g_{2} O

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H g O_{2}

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H g

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Solution

The correct option is D $H g$
When cinnabar is heated in air, it is first converted into $H g O$ . When further reduced, it gives mercury on further heating.
Step 1. $2 H g S (s) + 3 O_{2} (g) △ - \to 2 H g O (s) + 2 S O_{2}$
Step 2. $2 H g O (s) h e a t - - \to 2 H g (l) + O_{2} (g)$ .

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