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Question

When Cl2 gas is bubbled through concentrated and hot KOH a firework explosive (A) is formed along with KCl and H2O. How many grams of (A) will be formed by 150 L of Cl2 whose pressure is 950 mm of Hg at 27oC?
(take R=112 L atm mol1 K1)

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Solution

3Cl2+6KOH(aq.)KClO3(A)+5KCl+3H2O
We know that,
PV=nRT
P=950760atm, V=150 L
R=112LatmK1mol1, T=300 K
n=PVRT=950 atm×150 L760×112L atmK1mol1×300 K
=7.5 mol
No.of moles of KClO3 produced =13×no.of moles of Cl2
=13×7.5
=2.5 mol
Mass of KClO3 formed= 2.5mol×122.5g/mol
=306.25 g

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