3Cl2+6KOH(aq.)→KClO3(A)+5KCl+3H2O
We know that,
PV=nRT
P=950760atm, V=150 L
R=112LatmK−1mol−1, T=300 K
n=PVRT=950 atm×150 L760×112L atmK−1mol−1×300 K
=7.5 mol
No.of moles of KClO3 produced =13×no.of moles of Cl2
=13×7.5
=2.5 mol
Mass of KClO3 formed= 2.5mol×122.5g/mol
=306.25 g