When cold and dilute NaOH reacts with chlorine, the product is?

N a C l O

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N a C l O_{2}

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N a C l O_{3}

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N a C l O_{4}

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Solution

The correct option is B $N a C l O$
$C l_{2} + 2 N a O H \to N a O C l + N a C l + H_{2} O$
When cold and dilute $N a O H$ reacts with chlorine, the above disproportionation reaction takes place.
$N a C l O$ is one of the product formed.

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