Question

When $x^{94}-7x^{19}+5x^4-x+K$ is divided by (x - 1) then the remainder is -1 The remainder obtained when it is divided by (x + 1) is

• A. 0
• B. 15
• C. -1
• D. 10

Answer 1

Answer: (B)

15

$x^{94}-7x^{19}+5x^4-x+k$
Put x-1=0 or x=1 then reminder is -1 given
$(1{)}^{94}-7(1{)}^{19}+5(1{)}^4-(1)+k$
$\Rightarrow 1-7+5-1+k$
Then 1-7+5-1+k+1=0
Or k-1=0 or k=1
$x^{94}-7x^{19}+5x^4-x+k$
Div by x+1 then put value of x=-1
$(-1{)}^{94}-7(-1{)}^{19}+5(-1{)}^4-(-1)+1$
$\Rightarrow 1+7+5+1+1=15$