When $D N A$ was extracted from cells of $E .$ coli and analysed for composition of bases, it was found that $38 %$ of the bases were cytosine. What percentage of bases would be adenine?

12

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24

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38

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82

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Solution

The correct option is A $12$

In dsDNA of E.coli, 38% of cytosines are present, then 38% of guanines are present. In the remaining 24%, 12% adenines and 12% thymines are present.
So, the correct option is ‘12’.

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When DNA was extracted from cells of E. coli and analysed for composition of bases, it was found that 38% of the bases were cytosine. What percentage of bases would be adenine?

The correct option is A 12 In dsDNA of E.coli, 38% of cytosines are present, then 38% of guanines are present. In the remaining 24%, 12% adenines and 12% thymines are present. So, the correct option is ‘12’.

When $D N A$ was extracted from cells of $E .$ coli and analysed for composition of bases, it was found that $38 %$ of the bases were cytosine. What percentage of bases would be adenine?

The correct option is A $12$

In dsDNA of E.coli, 38% of cytosines are present, then 38% of guanines are present. In the remaining 24%, 12% adenines and 12% thymines are present.
So, the correct option is ‘12’.