When dry chlorine gas is bubbled through molten Sulphur, a red liquid is formed. What is its composition?

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Solution

Passing dry chlorine over molten sulphur results in the formation of $S_{2} C l_{2}$ , which is a yellowish-orange liquid that fumes in the presence of moisture. It has a very pungent odour. When this $S_{2} C l_{2}$ further reacts with chlorine, sulphur dichloride $(S C l_{2})$ is produced. It is a highly toxic liquid that is red in colour.

$S_{8} + 4 C l_{2} \to 4 S_{2} C l_{2}$
$S_{2} C l_{2} + C l_{2} \to 2 S C l_{2}$

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