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Question

When electricity is passed through molten AlCl3, 13.5g of Al is deposited. The number of Faraday's must be:

A
0.5
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B
1.0
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C
1.5
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D
2.0
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Solution

The correct option is C 1.5
According to Faraday law of electrolysis
Mass deposited =Equivalentmass×ChargeFaraday
13.5g=(273)g×QF(asEq.mass=MolarmassChargeonion)Q=1.5F
Thus 1.5 Faraday is required to deposit 13.5g of Al

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