Question

When electricity is passed through molten $AlC{l}_3$, $13.5g$ of $Al$ is deposited. The number of Faraday's must be:

• A. $0.5$
• B. $1.0$
• C. $1.5$
• D. $2.0$

Answer 1

The correct option is C $1.5$

According to Faraday law of electrolysis

Mass deposited $=Equivalentmass\times \frac{Charge}{Faraday}$

$13.5g=\left(\frac{27}{3}\right)g\times \frac{Q}{F}(asEq.mass=\frac{Molarmass}{Chargeonion})Q=1.5F$

Thus $1.5$ Faraday is required to deposit $13.5g$ of $Al$