1
Question
When ethyl chloride and alcoholic KOH are heated, the compound obtained is
When ethyl chloride and alcoholic KOH are heated, the compound obtained is
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Solution
The correct option is A C2H4
There are two types of elimination reaction,
1. α− Elimination reaction
2. β− Elimination reaction
In α− Elimination reaction, the leaving group and the proton are removed from the same α− carbon which leads to reactive carbene intermediate.
In β− Elimination reaction, the leaving group and the proton are removed from the adjacent atoms i.e., leaving group from α− carbon and proton from β− carbon. It leads to the formation of alkene compounds.
We know that,
When ethyl chloride is heated in presence of alcoholic KOH it undergo dehydrohalogenation to give alkene product. This reaction is a β− Elimination reaction.
CH3CH2Cl+KOH→CH2=CH2+KCl+H2O
Thus, in the given reaction ethene (C2H4) is produced.
There are two types of elimination reaction,
1. α− Elimination reaction
2. β− Elimination reaction
In α− Elimination reaction, the leaving group and the proton are removed from the same α− carbon which leads to reactive carbene intermediate.
In β− Elimination reaction, the leaving group and the proton are removed from the adjacent atoms i.e., leaving group from α− carbon and proton from β− carbon. It leads to the formation of alkene compounds.
We know that,
When ethyl chloride is heated in presence of alcoholic KOH it undergo dehydrohalogenation to give alkene product. This reaction is a β− Elimination reaction.
CH3CH2Cl+KOH→CH2=CH2+KCl+H2O
Thus, in the given reaction ethene (C2H4) is produced.
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