When ethyl chloride is added to Sodium tert-butoxide, ethyl tert-butyl ether is obtained as the major product (shown below):

When the concentration of ethyl chloride is doubled, the reaction rate:

quadruples

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halves

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remains unchanged

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doubles

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Solution

The correct option is D

doubles

Clearly, the reaction is an $S_{N} 2$ – a bimolecular reaction. Since no further data is given, let us assume an order of 2, so the rate expression is:

$R e a c t i o n r a t e = [(C H_{3})_{3} O^{-}] \times [C_{2} H_{5} C l]$

Clearly, the rate would double if concentration of ethyl chloride is doubled.

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Similar questions

When ethyl chloride is added to Sodium tert-butoxide, ethyl tert-butyl ether is obtained as the major product (shown below):

When the concentration of ethyl chloride is doubled, the reaction rate:

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When ethyl chloride is added to Sodium tert-butoxide, ethyl tert-butyl ether is obtained as the major product (shown below): When the concentration of ethyl chloride is doubled, the reaction rate:

The correct option is D doubles Clearly, the reaction is an SN2 – a bimolecular reaction. Since no further data is given, let us assume an order of 2, so the rate expression is: Reaction rate=[(CH3)3O−]×[C2H5Cl] Clearly, the rate would double if concentration of ethyl chloride is doubled.

When ethyl chloride is added to Sodium tert-butoxide, ethyl tert-butyl ether is obtained as the major product (shown below):

When the concentration of ethyl chloride is doubled, the reaction rate: