When excess of ammonia reacts with bleach, it can form:

N O

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N H_{4} C l

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N_{2} H_{4}

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H N O_{2}

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Solution

The correct option is C $N_{2} H_{4}$
$2 N H_{3} + N a O C l ⟶ N_{2} H_{4} + H_{2} O + N a C l$

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When chlorine reacts with ammonia , it is reduced to X, which further combines with excess of ammonia to form Y. Name this Y.

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