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Colours in Coordination Compounds

When FeCl3 is...

Question

When $F e C l_{3}$ is treated with $K_{4} [F e (C N)_{6}]$ , a blue coloured compound is formed. What are the total number of atoms per formula molecule? (supposing no K is present in blue coloured compound)

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Solution

The corresponding reaction is:
$4 F e C l_{3} + 3 K_{4} [F e (C N)_{6}] \to F e_{4} [F e (C N)_{6}]_{3} + 12 K C l$
The blue colour is due to $F e_{4} [F e (C N)_{6}]_{3}$ .
Therefore, total number of atoms per formula molecule are 43.

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F e C l_{3}

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K_{4} [F e (C N)_{6}]

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