Question

When fluids of density $2.2\text{g/cc}\&4.8\text{g/cc}$ are mixed together in equal volumes, then the density of the resulting mixture will be

• A. $1.2\text{g/cc}$
• B. $2.6\text{g/cc}$
• C. $3.5\text{g/cc}$
• D. $4.2\text{g/cc}$

Answer 1

The correct option is C $3.5\text{g/cc}$

${\rho }_{\text{mix}}=\frac{m_{\text{mix}}}{V_{\text{mix}}}$
$\Rightarrow {\rho }_{\text{mix}}=\frac{{\rho }_1{V}_1+{\rho }_2{V}_2}{V_1+V_2}$
$\because V_1=V_2$
$\Rightarrow {\rho }_{\text{mix}}=\frac{{\rho }_1+{\rho }_2}{2}$
$\therefore {\rho }_{\text{mix}}=\left(\frac{2.2+4.8}{2}\right)=3.5\text{g/cc}$