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Concentration Terms

When H 2 S ...

Question

When $H_{2} S$ gas is passed into a mixture solution acidified with dil $H C l$ , yellowish turbidity appears, explain.

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Solution

On passing $H_{2} S$ gas through dilute $H C l$ , sulphur gas is evolved which is responsible for the appearance of yellow turbidity.

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Q. You have been given an inorganic mixture with a knowledge that group II is absent but when

H_{2} S

gas is passed into the mixture acidified with dilute

H C l

, yellowish turbidity appears due to presence of sulphur.

If true enter 1, else enter 0.

Q. Assertion :Sometimes it happens that when

H_{2} S

gas is passed into solutions in .dil. HCl, yellowish white turbidity appears. Reason: The yellowish turbidity is due to colloidal sulphur, formed by oxidation of

H_{2} S

by the presence of

N O_{3}^{-}

N O_{2}^{-} o r S O_{3}^{2 -}

H_{2} S + H N O_{3} ⟶ S

(colloidal)
Before passing

H_{2} S

gas, solution is boiled so as to decompose these radicals.

Read the above assertion and reason and choose the correct option regarding it.

H_{2} S

gas is passed into

S O_{2}

in aqueous solution, colloidal yellowish white turbidity appears.

Calculate the weight of this turbidity if

11.2 L

of each gas reacts at

N T P

In qualitative inorganic analysis of basic radicals, solution is prepared in dil.

H C l

and then diluted with

H_{2} O

H_{2} S

gas is passed. Orange turbidity appeared in one case on dilution. Turbidity dissolves when we add

H C l

X

22.4

L at S.T.P. The gas turns acidified

K_{2} C r_{2} O_{7}

green and decolourizes acidified

K M n O_{4}

solution. White turbidity appears when

H_{2} S

gas is passed through aqueous solution of gas, then

X

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