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Preparation of Alcohols from Alkenes

When haloalka...

Question

When haloalkane or alkyl halide with a $β$ hydrogen is heated with alcoholic solution of KOH, elimination of a hydrogen atom from $β$ carbon and halogen atom from $α$ -carbon occurs as a result, alkene is formed as product. Since $β$ hydrogen atom is involved in the elimination reaction, it is often called $β$ elimination.

P and Q are respectively.

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None of the above

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Solution

The correct option is A

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Similar questions

β

β

α

β

β

C H_{3} F C H C H_{2} C H_{2} C H_{3} C H_{3} O^{-} \to C H_{3} O H R (M a j o r P r o d u c t)

β

{C H}_{3} {C H}_{2} {C H}_{2} B r (i)

{C H}_{3} - C H {- C H}_{2} B r | {C H}_{3} (i i)

{C H}_{3} - {C H}_{2} - C H - {C H}_{3} | B r (i i i)

An alkane with molecular formula $C_{6} H_{14}$ gives two monochloro alkanes on chlorination. What is the structure of alkane?

β -

C H_{3} - C H_{2} - B r

C H_{3} - C H_{2} - C H_{2} - B r

β

{C H}_{3} - H | C | {C H}_{3} - {C H}_{2} B r

C H_{3} - C H_{2} - B r

C H_{3} - C H_{2} - C H_{2} - B r

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