When $H B r$ adds on hex-1-ene in the presence of benzoyl peroxide, the product is

2-bromohexane

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2, 3-dibromohexane

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1, 2-dibromohexane

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2, 4-dibromohexane

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1-bromohexane

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Solution

The correct option is E 1-bromohexane
In presence of peroxide Anti-Markownikoff's addition takes place. Hence the product formed is $1-bromohexane$

Hence, option E is correct.

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