When HF reacts with glass, the compound formed is:

F_{2}

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N a F

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N a_{3} A l F_{3}

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N a_{2} S i F_{6}

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Solution

The correct option is A $N a_{2} S i F_{6}$
When glass is attacked by $H F$ , it forms $N a_{2} S i F_{6}$ and this property is used for the etching of glass.

The reaction is given below:
$N a_{2} S i O_{3} + 6 H F \to N a_{2} S i F_{6} + 3 H_{2} O$

Option D is correct.

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