When $H N O_{3}$ reacts with $P_{4} O_{10}$ , the compound(s) formed is\are :

H P O_{3}

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N_{2} O_{3}

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N_{2} O_{5}

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H_{3} P O_{3}

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Solution

The correct options are
A $H P O_{3}$
C $N_{2} O_{5}$
The reaction is as follows:
${4 H N O}_{3} + P_{4} O_{10} \to {2 N}_{2} O_{5} + {4 H P O}_{3}$

Suggest Corrections

Similar questions

H N O_{3} + P_{4} O_{10} \to H P O_{3} + A

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H N O_{3}

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N_{2} O_{5}

H N O_{3}

H_{2} N_{2} O_{2}, H N O_{2}, H N O_{3}

N_{2} O_{5}, N_{2} O, N O, N_{2} O_{3}

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