When iron is added to $C u S O_{4}$ solution, copper is precipitated. It is due to ____.

oxidation of

C u^{2 +}

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reduction of

C u^{2 +}

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hydrolysis of

C u S O_{4}

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ionisation of

C u S O_{4}

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Solution

The correct option is B reduction of $C u^{2 +}$
$F e (s) + + 2 C u S O_{4} (a q) ⟶ F e S O_{4} (a q) + 0 C u (s)$
Since, there is decrease in oxidation number of $C u$ i.e. from $+ 2$ in $C u S O_{4}$ to $0$ in $C u$ . Therefore, $C u^{+ 2}$ is undergoing Reduction.

Suggest Corrections

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N - C u {S O}_{4}

{C u}^{2 +}

C u S O_{4}

C u S O_{4}

C u S O_{4}

Z n

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C u S O_{4}

C u^{2 +}

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

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