Question

When isobutylene is dissolve in methanol containing a strong acid, a reaction takes place to produce $ter-$butyl methyl ether. Write the mechanism that accounts the formation of this product.

Answer 1

The mechanism for the conversion of isobutylene to ter-butyl methyl ether is as shown below.
The pi electrons of carbon carbon double bond are donated to proton to form carbocation intermediate. this is followed by the nucleophilic attack of methanolic oxygen and deprotonation to give the final product.