When $K M n O_{4}$ acts as an oxidising agent and ultimately forms $[M n O_{4}]^{- 2}, M n O_{2}, M n_{2} O_{3}, M n^{+ 2}$ then the number of electrons transferred in each case respectively is

4, 3, 1, 5

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1, 5, 3, 7

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1, 3, 4, 5

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3, 5, 7, 1

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Solution

The correct option is C
1, 3, 4, 5

This has to be answered based on the oxidation number of the central metal atom in each case.
To start with Mn has +7 oxidation number in $K M n O_{4}$ . Likewise, we have
$+ 6 M n O_{4}^{2 -}$
$+ 4 M n O_{2}$
$+ 3 M n_{2} O_{3}$
$+ 2 M n^{2 +}$

The number of electrons transferred in each case is 1, 3, 4, 5 respectively.

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When $K M n O_{4}$ acts as an oxidising agent and ultimately forms $[M n O_{4}]^{2 -}$ ,
$M n O_{2}$ _, $M n_{2} O_{3}$ , $[M n]^{2 +}$ ,then the number of electrons transferred in each case respectively is

When $K M n O_{4}$ acts as an oxidising agent and ultimately forms $[M n O_{4}]^{- 2}, M n O_{2}, M n_{2} O_{3}, M n^{+ 2}$ then the number of electrons transferred in each case respectively is