When lead nitrate reacts with potassium iodide, yellow precipitate of

$P b I_{2}$ is formed

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$K N O_{3}$ is formed

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$P b (N O_{3})_{2}$ is formed

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$K I$ is formed

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Solution

The correct option is A
$P b I_{2}$ is formed

$P b (N O_{3})_{2} (a q) + 2 K I (a q) \to P b I_{2} (↓) + 2 K N O_{3} (a q)$
$P b I_{2}$ is yellow precipitate.

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When lead nitrate reacts with potassium iodide, yellow precipitate of

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What is the colour of precipitate formed when lead nitrate reacts with potassium iodide?

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