When magnesium metal is added to water, hydrogen gas, H2 is released. If 72 g of hydrogen gas is liberated in this reaction, how many number of moles of hydrogen gas is produced? Mg (s) + 2H2O (l) →Mg(OH)2 (aq) + H2 (g)
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Solution
Given mass of hydrogen (H2) = 72 g
Gram molecular mass of H2 = 2 g
Number of moles = Given massGram molecular mass [1 Mark] ∴ Number of moles of H2 = 722 = 32 mol
[1 Mark]