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Bond Order by MOT

When N 2 goes...

Question

When $N_{2}$ goes to $N_{2}^{+}$ , the N-N bond distance ..... and when $O_{2}$ goes to $O_{2}^{+}$ , the O-O bond distance ....

A

Decrease, increase

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B

Increase, decrease

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C

Increase, increase

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D

None of these

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Solution

The correct option is B Increase, decrease
Bond order in $N_{2} = 3$ and $N_{2}^{+} = 2.5$ . Bond order in $O_{2} = 2$ and $O_{2}^{+} = 2.5$ . As bond order increases bond length decreases and vice-versa.

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Similar questions

When $N_{2}$ goes to $N_{2}^{+}$ , the N - N bond distance ... and

when $O_{2}$ goes to $O_{2}^{+}$ , the o - o bond distance....

N_{2}

N_{2}^{+}

O_{2}

O_{2}^{+}

. What happens to the

N - N

bond distance and the

O - O

bond distance respectively?

N_{2}

N_{2}^{+}

N - N

bond distance increase, and when

O_{2}

O_{2}^{+}

O - O

bond distance decrease.

Write the above statement is true or false:

N_{2}

N_{2}^{+}

N - N

bond distance increases and when

O_{2}

O_{2}^{+}

O - O

bond distance decreases.

If the statement is true enter 1, else enter 0.

N_{2}

N_{2}^{+}

O_{2}

O_{2}^{+}

. What happens to the

N - N

bond distance and the

O - O

bond distance respectively?

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