wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

When N2O5 is heated at a certain temperature, it dissociates as:
N2O5(g)N2O3(g)+O2(g);Kc=2.5. At the same time N2O3 also decomposes as:
N2O3(g)N2(g)+O2(g);. If 4.0 moles of N2O5 are taken initially in a 1.0 litre flask and allowed to dissociate, the concentration of O2 at equilibrium is 2.5 M. The equilibrium concentration of N2O5 is :

A
1.00 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.50 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.17 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.87 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1.87 M
N2O5 N2O3 + O2
4-x x-y x+y
N2O3 N2O + O2
x-y y x+y
x+y=[O2]=2.5
2.5=(x+y)(xy)4xx=2.166[N2O5]=4x=1.87

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon