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Bleaching Powder

When NaCl dec...

Question

When NaCl decomposes in the presence of water, product A, B and C are formed. When B reacts with D, bleaching powder is formed. What are A, B, C and D?

A

A = NaOH, B= $H_{2} O$ , C= $C O_{2}$ and D = $N a H C O_{3}$

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B

A = $C l_{2}$ , B = $H_{2}$ , C = $C O_{2}$ and D = NaOH

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C

A = NaOH, B= $C l_{2}$ , C= $H_{2}$ and D = $C a (O H)_{2}$

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D

A = NaOH, B= $H_{2}$ , C= $C l_{2}$ and D = $C a (O H)_{2}$

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Solution

The correct option is C
A = NaOH, B= $C l_{2}$ , C= $H_{2}$ and D = $C a (O H)_{2}$

A = NaOH, B= $C l_{2}$ , C= $H_{2}$ and D = $C a (O H)_{2}$

$N a C l + H_{2} O \to N a O H + C l_{2} + H_{2}$

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