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Question

When NaCl is doped with 1.0×103 mole of SrCl2, the number of cation vacancy is ?


  1. 6.023×1018

  2. 6.023×1020

  3. 2×6.023×1020

  4. 3.011×1020


Solution

The correct option is B

6.023×1020


Two Na+ ions are replaced by one Sr2+ ions doped =1.0×103×6.02×1023=6.02×1020

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