When $N H_{4} C l$ is treated with $C a O$ we get $C a C l_{2}, C a (O H)_{2}$ and $X$ as its products. Where X is :

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ammonia

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carbon dioxide

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water

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Solution

The correct option is A ammonia
$2 N H_{4} C l + 2 C a O \to C a C l_{2} + C a (O H)_{2} + 2 N H_{3}$
Ammonia is formed when $N H_{4} C l$ is treated with $C a O$ .

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Similar questions

Q. What are the missing products of the following reaction?

{N H}_{4} C l + {C a (O H)}_{2} \to___+ C a {C l}_{2}

IN the synthesis of sodium carbonate, the recovery of ammonia is done by treating $N H_{4} C l$ with $C a (O H)_{2}$ The by product obtained in this process is
(a) $C a C l_{2}$ (b) NaCl (c) NaOH (d) $N a H C O_{3}$

Q. Balance the reaction.

N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + N H_{3} + H_{2} O

Balance the following equation b hit and trial method :. NH4Cl + Ca(OH)2 ------------> CaCl2 + H2O + NH3

Q. When 2-butyne is treated with

H_{2} /

Lindlar's catalyst, compound

X

is produced as the major product and when treated with

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liq.

N H_{3}

it produces

Y

as the major product. Which of the following statements is correct?

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When NH4Cl is treated with CaO we get CaCl2,Ca(OH)2andX as its products. Where X is :

The correct option is A ammonia2NH4Cl+2CaO→CaCl2+Ca(OH)2+2NH3Ammonia is formed when NH4Cl is treated with CaO.

When $N H_{4} C l$ is treated with $C a O$ we get $C a C l_{2}, C a (O H)_{2}$ and $X$ as its products. Where X is :

The correct option is A ammonia
$2 N H_{4} C l + 2 C a O \to C a C l_{2} + C a (O H)_{2} + 2 N H_{3}$
Ammonia is formed when $N H_{4} C l$ is treated with $C a O$ .