Relation between P, V, T, Gamma in Adiabatic Proceses
When one mole...
Question
When one mole of monoatomic ideal gas at temperature T undergoes adiabatic change reversibly, change in volume is from 1Lto5L, the final temperature in Kelvin would be:
A
T52/3
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B
T+23×0.0821
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C
T
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D
T−23×0.0821
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Solution
The correct option is AT52/3 We know the relation for an adiabatic reversible process : T1T2=(V2V1)γ−1
where, T1= initial temperature T2= final temperature V1= initial volume V2= final volume γ=CpCv=53 (for monoatomic gas)
so, T1T2=(51)(5/3)−1=5(2/3) T2=T15(2/3)