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Question

When P is a natural number, then Pn+1+(P+1)2n−1 is divisible by

A
P
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B
P2+P
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C
P2+P+1
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D
P2+1
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Solution

The correct option is C P2+P+1
For n = 2, we get,
Pn+1+(P+1)2n1=P3+(P+1)3
=P3+P3+1+3P2+3P=2P3+3P2+3P+1
Which is divisible by P2+P+1
Given result is true for all nϵN.

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