When propionic acid is treated with aqueous sodium bicarbonate, $C O_{2}$ is liberated. The $C$ from $C O_{2}$ comes from:

methyl group

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carboxylic acid group

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methylene group

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bicarbonate

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Solution

The correct option is D bicarbonate
When propionic acid is treated with aqueous sodium bicarbonate, $C O_{2}$ is liberated. The $C$ from $C O_{2}$ comes from bicarbonate.

$C H_{3} C H_{2} C O O H + N a H C O_{3} \to C H_{3} C H_{2} C O O N a + H_{2} O + C O_{2} ↑$

Option D is correct.

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