When $S O_{2}$ is passed through acidified $K_{2} {C r}_{2} O_{7}$ solution, the colour of the solution changes to :

Red

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Black

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Orange

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Green

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Solution

The correct option is B Green
When $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution, the orange colour of the solution changes to green due to formation of chromic sulphate.

$K_{2} C r_{2} O_{7} + 3 S O_{2} + H_{2} S O_{4} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{2} + 7 H_{2} O + 3 S$

Hence, option $D$ is correct.

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