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Stoichiometric Calculations

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Question

When same amount of zinc is treated separately with excess of 1 $H_{2} S O_{4}$ and $N a O H$ , the ratio of volumes of $H_{2}$ evolved is:

A

1 : 1

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B

1 : 2

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C

2 : 1

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D

9 : 4

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Solution

The correct option is A 1 : 1
$Z n + H_{2} S O_{4} \to Z a S O_{4} + H_{2}$

$Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$
Hence when same amount of zinc is treated separately with excess of sulphuric acid and $N a O H$ , the ratio of volumes of $H_{2}$ evolve is $1 : 1$ .

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