CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Zinc II Oxide

When the same...

Question

When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is $X : Y$ . Find the value of $\frac{X}{Y}$ .

Open in App

Solution

$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$
$Z n + 2 N a O H \to N a_{2} Z n O_{2} H_{2}$
The ratio of volumes of $H_{2}$ evolved in both the cases is $1 : 1.$ Hence , $\frac{1}{1} = 1$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is:

Q. The same amount of Zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide. What will be the ratio of volumes of hydrogen evolved ?

Q. When some amount of zinc is treated separately with an excess of sulphuric acid and excess of sodium hydroxide solution the ratio of volumes of hydrogen evolved will be:

Q. When the same amount of zinc metal is treated separately with excess of

H_{2} S O_{4}

N a O H

, the ratio of the volumes of

H_{2}

Q. When same amount of zinc is treated separately with excess of 1

H_{2} S O_{4}

N a O H

, the ratio of volumes of

H_{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Compounds of Zinc

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XIII Chemistry

Join BYJU'S Learning Program

CrossIcon