When same quantity of electricity is passed through aqueous AgNO3 and H2SO4 solutions connected in series- 5-04 -10-2 g of H2 is liberated- What is the mass of silver in grams deposited- Eq- wts- of hydrogen - 1-008- silver -108

The correct option is B 5.4 W _ 1 = Z _ 1 It W _ 2 = Z _ 2 It W _ 1 W _ 2 = Z _ 1 Z _ 2 W _ Ag W _ H _ 2 = Z _ Ag Z _ H _ 2 ...

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Standard XII

Chemistry

Faraday's First Law

When same qua...

Question

When same quantity of electricity is passed through aqueous $A g N O_{3}$ and $H_{2} S O_{4}$ solutions connected in series, $5.04 \times 10^{- 2} g$ of $H_{2}$ is liberated. What is the mass of silver (in grams) deposited? (Eq. wts. of hydrogen $= 1.008$ , silver $= 108$ )

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Solution

The correct option is B $5.4$
$W_{1} = Z_{1} I t W_{2} = Z_{2} I t \frac{W_{1}}{W_{2}} = \frac{Z_{1}}{Z_{2}} \frac{W_{A g}}{W_{H_{2}}} = \frac{Z_{A g}}{Z_{H_{2}}} W_{A g} = \frac{108}{1 \times F} \times \frac{1 \times F}{1.008} \times 5.4 \times 10^{- 2} W_{A g} = 5.4 g$

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When same quantity of electricity is passed through aqueous AgNO3 and H2SO4 solutions connected in series, 5.04×10−2g of H2 is liberated. What is the mass of silver (in grams) deposited? (Eq. wts. of hydrogen =1.008, silver =108)

The correct option is B 5.4W1=Z1ItW2=Z2ItW1W2=Z1Z2WAgWH2=ZAgZH2WAg=1081×F×1×F1.008×5.4×10−2WAg=5.4g

When same quantity of electricity is passed through aqueous $A g N O_{3}$ and $H_{2} S O_{4}$ solutions connected in series, $5.04 \times 10^{- 2} g$ of $H_{2}$ is liberated. What is the mass of silver (in grams) deposited? (Eq. wts. of hydrogen $= 1.008$ , silver $= 108$ )

The correct option is B $5.4$
$W_{1} = Z_{1} I t W_{2} = Z_{2} I t \frac{W_{1}}{W_{2}} = \frac{Z_{1}}{Z_{2}} \frac{W_{A g}}{W_{H_{2}}} = \frac{Z_{A g}}{Z_{H_{2}}} W_{A g} = \frac{108}{1 \times F} \times \frac{1 \times F}{1.008} \times 5.4 \times 10^{- 2} W_{A g} = 5.4 g$