When ${S O}_{2}$ gas is passed into aqueous $K_{2} {C r}_{2} O_{7}$ solution (orange), it changes to green coloured solution. What is the oxidation number of the species that has this green color?

Open in App

Solution

In this redox reaction, sulphur dioxide is oxidized to sulphate ions. The oxidation number of S changes from +4 to +6.
The dichromate ion (orange in colour) is reduced to chromate ion (green in colour).
The oxidation number of Cr changes from +6 to +3.
Hence, the oxidation number of the species that has this green color is 3.

Suggest Corrections

Similar questions

{S O}_{2}

K_{2} {C r}_{2} O_{7}

S O_{2}

K_{2} {C r}_{2} O_{7}

K_{2} {C r}_{2} O_{7}

{N a}_{2} S O_{3}

{S O}_{2}

K_{2} {C r}_{2} O_{7}

Join BYJU'S Learning Program