Question

When ${SO}_2$ is passed through acidified $K_2{Cr}_2{O}_7$ solution:

• A. the solution truns blue.
• B. ${SO}_2$ is reduced.
• C. green ${Cr}_2({SO}_4{)}_3$ is formed.
• D. the solution is decolourised.

Answer 1

Answer: (C)

green ${Cr}_2({SO}_4{)}_3$ is formed.

Green $C{r}_2(S{O}_4{)}_3$ is formed When $S{O}_2$ is bubbled through acidified solution of $K_{2}C{r}_2{O}_7$, the orange colour of $K_{2}C{r}_2{O}_7$ solution turns to clean green due to formation of chromium sulphate.

Hence option C is correct answer.