When $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution :

the solution turned blue

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the solution is decolourised

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{2}

is reduced

No worries! We‘ve got your back. Try BYJU‘S free classes today!

green

C r_{2} (S O_{4})_{3}

is formed

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D green $C r_{2} (S O_{4})_{3}$ is formed

Green $C r_{2} (S O_{4})_{3}$ is formed.

Suggest Corrections

Similar questions

Which one of the following statements is correct when $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution?

When SO₂ is passed through an acidified solution of K2Cr2O7, then chromium sulphate is formed. Change in the oxidation state of Cr is from.

S O_{2}

K_{2} C r_{2} O_{7}

S

S O_{2}

H_{2} S

Join BYJU'S Learning Program