Question

When $S{O}_2$ is passed through acidified $K_{2}C{r}_2{O}_7$ solution,

• A. solution turns blue.
• B. solution decolorizes.
• C. $S{O}_2$ is reduced.
• D. green $C{r}_2(S{O}_4{)}_3$ is formed.

Answer 1

The correct option is D green $C{r}_2(S{O}_4{)}_3$ is formed.

green colour $C{r}_2(S{O}_4{)}_3$ is formed When $S{O}_2$ is passed through solution of $K_{2}C{r}_2{O}_7$, the orange colour of $K_{2}C{r}_2{O}_7$ solution turns to clean green due to formation of chromium sulphate .