When $S O_{3}$ treated with $D_{2} O$ , the products are:

deutero sulphuric acid

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

deuterium sulphuric acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

deuterium and sulphuric acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D_{2} S O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C deutero sulphuric acid
When $S O_{3}$ treated with $D_{2} O$ , the product is deutero sulphuric acid.
$S O_{3} + D_{2} O \to D_{2} S O_{4}$ .

Suggest Corrections

Similar questions

Q. When benzoic acid is treated with sulphuric acid in the presence of

S O_{3}

, the product is

Q. When Barium chlorite is treated with sulphuric acid ,the product formed is:

Q. What are the products formed when phenol and nitrobenzene are treated separately with a mixture of concentrated sulphuric acid and concentrated nitric acid?

Name the following:
(a) Products obtained by dissolving sulphur dioxide and chlorine in water.
(b) The catalyst used in the contact process.
(c) Solution obtained by dissolving sulphur trioxide in 98% sulphuric acid.
(d) Products obtained by treating zinc with dilute sulphuric acid.
(e) Products obtained by treating ferrous sulphide with dilute sulphuric acid.
(f) The precipitate obtained by treating aqueous lead nitrate with dilute sulphuric acid.
(g) The precipitate obtained by treating aqueous barium chloride with dilute sulphuric acid.
(h) Gases obtained by treating carbon with hot concentrated sulphuric acid.
(i) The property used to prepare HCl and HNO₃ from H₂SO₄.

Which of the following gives an unsaturated hydrocarbon product when treated with conc. sulphuric acid

Join BYJU'S Learning Program

When SO3 treated with D2O , the products are:

The correct option is C deutero sulphuric acidWhen SO3 treated with D2O , the product is deutero sulphuric acid.SO3+D2O→D2SO4.

When $S O_{3}$ treated with $D_{2} O$ , the products are:

The correct option is C deutero sulphuric acid
When $S O_{3}$ treated with $D_{2} O$ , the product is deutero sulphuric acid.
$S O_{3} + D_{2} O \to D_{2} S O_{4}$ .