When sulphur trioxide gas is dissolved in H 2 SO 4- the product obtained isA- H 2 SO 3B- H 2 SO 5C- H 2 S 2 O 7D- H 2 S 2 O 8

The correct option is C H2S2O7 H_2SO_4 + SO_3 → H_2S_2O_7 (Oleum) ...

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Standard XII

Chemistry

Sulphur

When sulphur ...

Question

When sulphur trioxide gas is dissolved in $H_{2} S O_{4}$ , the product obtained is

H₂SO₃

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H₂SO₅

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H₂S₂O₇

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H₂S₂O₈

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Solution

The correct option is C
H₂S₂O₇

$H_{2} S O_{4} + S O_{3} \to H_{2} S_{2} O_{7} (O l e u m)$

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Similar questions

Name the following:
(a) Products obtained by dissolving sulphur dioxide and chlorine in water.
(b) The catalyst used in the contact process.
(c) Solution obtained by dissolving sulphur trioxide in 98% sulphuric acid.
(d) Products obtained by treating zinc with dilute sulphuric acid.
(e) Products obtained by treating ferrous sulphide with dilute sulphuric acid.
(f) The precipitate obtained by treating aqueous lead nitrate with dilute sulphuric acid.
(g) The precipitate obtained by treating aqueous barium chloride with dilute sulphuric acid.
(h) Gases obtained by treating carbon with hot concentrated sulphuric acid.
(i) The property used to prepare HCl and HNO₃ from H₂SO₄.

Q. Which compound is formed when sulphur trioxide is dissolved in water?

Sulphur trioxide is dissolved in sulphuric acid and not in water because :

Q. Sulphur trioxide is not directly dissolved in water to form sulphuric acid because:

Sulphur trioxide gas is an important precursor to manufacture sulphuric acid. It is produced by the catalytic oxidation of $S O_{2}$ gas. In the contact process, once we obtain $S O_{3} (g)$ , Sulphuric acid is obtained by the hydrolysis of $S O_{3} (g)$ .

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When sulphur trioxide gas is dissolved in H2SO4, the product obtained is

The correct option is C H2S2O7 H2SO4+SO3→H2S2O7 (Oleum)

When sulphur trioxide gas is dissolved in $H_{2} S O_{4}$ , the product obtained is

The correct option is C
H₂S₂O₇

$H_{2} S O_{4} + S O_{3} \to H_{2} S_{2} O_{7} (O l e u m)$