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Question
When the amount of work done on the system is 333 cal and the change in internal energy is 167 cal, then the magnitude of heat associated with the process is:
When the amount of work done on the system is 333 cal and the change in internal energy is 167 cal, then the magnitude of heat associated with the process is:
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Solution
The correct option is A 166 cal
According to first law of thermodynamics,
Q=△U−W
Where Q = Heat given to the system
△U = Change in internal energy
W = Work done on the system
Given W = + 333 cal and △U = +167 cal
Q=△U−W=167−333=−166 cal
and magnitude of heat = 166 cal
According to first law of thermodynamics,
Q=△U−W
Where Q = Heat given to the system
△U = Change in internal energy
W = Work done on the system
Given W = + 333 cal and △U = +167 cal
Q=△U−W=167−333=−166 cal
and magnitude of heat = 166 cal
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