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Question

When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface is increased from 0.5 eV to 0.8 eV. The work function of the metal is

A
0.65 eV
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B
1.0 eV
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C
1.3 eV
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D
1.5 eV
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Solution

The correct option is B 1.0 eV
E=hvϕ0.5=hvϕ (1)Again0.8=1.2hvϕ (2)Fromequation(1)×1.20.6=1.2hv1.2ϕEquation(2) 0.8=1.2hvϕ +––––––––––––– 0.2=0.2ϕ ϕ=1eV

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