When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface is increased from 0.5 eV to 0.8 eV. The work function of the metal is
A
0.65 eV
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B
1.0 eV
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C
1.3 eV
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D
1.5 eV
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Solution
The correct option is B 1.0 eV E=hv−ϕ⇒0.5=hv−ϕ⋯(1)Again0.8=1.2hv−ϕ⋯(2)Fromequation(1)×1.2⇒0.6=1.2hv−1.2ϕEquation(2)0.8=1.2hv−ϕ−−+–––––––––––––––−0.2=−0.2ϕϕ=1eV