When the fertilizer plant completes its small batch process, they find that they have only collected $26 m L$ of $N H_{3}$ which was supposed to be $100 m L$ . They are disappointed with this result due to the low yield. What is the % yield of their process?

26

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38

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52

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76

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Solution

The correct option is A $26$ %
$26$ ml of $N H_{3}$ yeild into 100 ml
$= 26 / 100$
= $26$

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When the fertilizer plant completes its small batch process, they find that they have only collected 26 mL of NH3 which was supposed to be 100 mL. They are disappointed with this result due to the low yield. What is the % yield of their process?

The correct option is A 26%26 ml of NH3 yeild into 100 ml =26/100 = 26

When the fertilizer plant completes its small batch process, they find that they have only collected $26 m L$ of $N H_{3}$ which was supposed to be $100 m L$ . They are disappointed with this result due to the low yield. What is the % yield of their process?

The correct option is A $26$ %
$26$ ml of $N H_{3}$ yeild into 100 ml
$= 26 / 100$
= $26$