When the following equation: $C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$ is balanced, what will be the coefficient of $C u$ , in the lowest whole number?

1

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Solution

The correct option is C $3$
The unbalanced chemical equation is
$C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$
Cu atoms are balanced.
Balance N atoms.
$C u (s) + 3 H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)$
The oxidation number of Cu increases from 0 to +2.
The total increase in the oxidation number = 2.
The oxidation number of N decreases from +5 to +2.
The total decrease in the oxidation number of N is 3.
Balance increase in the oxidation number with a decrease in oxidation number.
$3 C u (s) + 8 H N O_{3} (a q) \to 3 C u (N O_{3})_{2} (a q) + H_{2} O (l) + 2 N O (g)$
Balance O atoms.
$3 C u (s) + 8 H N O_{3} (a q) \to 3 C u (N O_{3})_{2} (a q) + 4 H_{2} O (l) + 2 N O (g)$
H atoms are already balanced.
$3 C u (s) + 8 H N O_{3} (a q) \to 3 C u (N O_{3})_{2} (a q) + 4 H_{2} O (l) + 2 N O (g)$
This is the balanced chemical equation.
The coefficient of Cu is 3.

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