wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

When the following redox reaction
Cl2+OHClO3+Cl+H2O
is balanced by ion-electron method , what will be the coefficient of Cl2 and OH respectively?

A
3,6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2,4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5,5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3,6
0Cl2+OH+5ClO3+Cl+H2O

Oxidation half : Cl2ClO3
Chlorine changes its oxidation state from 0 to +5

Reduction half : Cl22Cl.
Chlorine changes its oxidation state from 0 to 1

Taking the oxidation half reaction :
Cl2ClO3
Balancing Cl
Cl22ClO3

Balancing O by adding H2O
Cl2+3H2O2ClO3

Balancing H by adding H+
Cl2+3H2O2ClO3+6H+

Adding similar amount of OH to both sides and combining H+ and OH to form H2O
Cl2+3H2O+6OH2ClO3+6H++6OH
Cl2+3H2O+6OH2ClO3+6H2O

Cancelling the extra H2O
Cl2+6OH2ClO3+3H2O

Balancing the charge on RHS by adding 4e
Cl2+6OH2ClO3+3H2O+4e ......(i)


Taking the reduction half :
Cl2Cl

Balancing Cl
Cl22Cl

Balancing charge by adding 2e to LHS
Cl2+2e2Cl......(ii)

Multiplying eq(ii) by 2 and then adding to eq (i)
2Cl2+4e4Cl
Cl2+6OH2ClO3+3H2O+4e
On adding
__________________________________________
3Cl2+6OH2ClO3+4Cl+3H2O

So the correct answer is 3,6

flag
Suggest Corrections
thumbs-up
32
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Balancing_ion elec
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon