Question

When the length of the vibrating segment of a sonometer wire is increased by 1%, the percentage change in its frequency is

• A. 100/101
• B. 99/100
• C. 1
• D. 2

Answer 1

The correct option is C 1

The frequency of vibration in a sonometer is given by $f=\left(1/2L\right)\sqrt{(}T/\mu )$
The fractional change in frequency with change in length is given by $\Delta f/f=-\Delta L/L$.
Thus, the frequency decreases by 1%
The correct option is (c)