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Question

When the load on a wire is slowly increased from 3 to 5 kg wt, the elongation increases from 0.61 to 1.02 mm. The work done during the extension of wire is


  1. 0.16 J

  2. 0.016 J

  3. 1.6 J

  4. 16 J


Solution

The correct option is B

0.016 J


Work done = 12 × stretching force × extension.

Therefore, net work done in increasing the length from 0.61 mm to 1.02 mm is

W2W1=12×5×9.8×1.02×10312×3×9.8×0.61×103=0.016 J

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