When the pressure of 2 litres of $O_{2}$ gas is doubled and its temperature is also doubled from 300K to 600K, the final volume of the gas is.

1 L

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2 L

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3 L

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4 L

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Solution

The correct option is B 2 L
Using combined gas law -
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{P_{1} \times 2}{300} = \frac{2 P_{1} \times V_{2}}{600}$

$V_{2} = 2 l i t r e s$

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The pressure of $2 L$ of $O_{2}$ gas is doubled when its temperature is increased from 300 K to 600 K. Find the final volume of the gas.

When the pressure of 2 litres of $O_{2}$ gas is doubled and its temperature is also doubled from 300K to 600K, What is the final volume of the gas?

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